Question 4598 – UGC NET CS 2006 June-Paper-2
March 31, 2024Question 3008 – Research Aptitude
March 31, 2024UGC NET CS 2006 June-Paper-2
| Question 6 |
The number of 1 ’s present in the binary representation of (3*512 + 7*64 +5*8 +3) 10 is :
| 8 | |
| 9 | |
| 10 | |
| 11 |
Question 6 Explanation:
(3*512 + 7*64 +5*8 +3) =2027
(2027) 10 = (111 1110 1011) 2
Here, total number of 1’s are 9.
(2027) 10 = (111 1110 1011) 2
Here, total number of 1’s are 9.
Correct Answer: B
Question 6 Explanation:
(3*512 + 7*64 +5*8 +3) =2027
(2027) 10 = (111 1110 1011) 2
Here, total number of 1’s are 9.
(2027) 10 = (111 1110 1011) 2
Here, total number of 1’s are 9.
