Software-Engineering
August 28, 2024Software-Engineering
August 28, 2024Software-Engineering
| Question 435 |
If a program P calls two subprograms P1 and P2 and P1 can fail 50% of the time and P2 can fail 40% of the time, what is the failure rate of program P
| 50% | |
| 60% | |
| 70% | |
| 10% |
Question 435 Explanation:
Method-1:
Based upon the success rate, we can find the solution.
Success rate=(1-failure rate)
Given failure rates are P1=50% P2=40%
P1 success rate= (1-failure rate)
= (1-0.5)
= 0.5
P2 success rate= (1-failure rate)
= (1-0.4)
= 0.6
Success rate of both P1 and P2 = 0.5 *0.6
= 0.3
Failure rate of both P1 and P2
= 1 – success rate
= 1 – 0.3
= 0.7 (or) 70%
Method-2:
Based upon the failure rate we can find the solution.
Program P is divided into two subprograms.
We can calculate total failure rate by considering the two subprograms
P(P1 U P2)= P1+P2-(P1*P2) /*Check note point */
= (50/100)+(40/100)-(50*40)/100
=90-20
=70%
Note: Failure of P1 + Failure of P2 – (Failure of P1 ∩ Failure of P2)
Based upon the success rate, we can find the solution.
Success rate=(1-failure rate)
Given failure rates are P1=50% P2=40%
P1 success rate= (1-failure rate)
= (1-0.5)
= 0.5
P2 success rate= (1-failure rate)
= (1-0.4)
= 0.6
Success rate of both P1 and P2 = 0.5 *0.6
= 0.3
Failure rate of both P1 and P2
= 1 – success rate
= 1 – 0.3
= 0.7 (or) 70%
Method-2:
Based upon the failure rate we can find the solution.
Program P is divided into two subprograms.
We can calculate total failure rate by considering the two subprograms
P(P1 U P2)= P1+P2-(P1*P2) /*Check note point */
= (50/100)+(40/100)-(50*40)/100
=90-20
=70%
Note: Failure of P1 + Failure of P2 – (Failure of P1 ∩ Failure of P2)
Correct Answer: C
Question 435 Explanation:
Method-1:
Based upon the success rate, we can find the solution.
Success rate=(1-failure rate)
Given failure rates are P1=50% P2=40%
P1 success rate= (1-failure rate)
= (1-0.5)
= 0.5
P2 success rate= (1-failure rate)
= (1-0.4)
= 0.6
Success rate of both P1 and P2 = 0.5 *0.6
= 0.3
Failure rate of both P1 and P2
= 1 – success rate
= 1 – 0.3
= 0.7 (or) 70%
Method-2:
Based upon the failure rate we can find the solution.
Program P is divided into two subprograms.
We can calculate total failure rate by considering the two subprograms
P(P1 U P2)= P1+P2-(P1*P2) /*Check note point */
= (50/100)+(40/100)-(50*40)/100
=90-20
=70%
Note: Failure of P1 + Failure of P2 – (Failure of P1 ∩ Failure of P2)
Based upon the success rate, we can find the solution.
Success rate=(1-failure rate)
Given failure rates are P1=50% P2=40%
P1 success rate= (1-failure rate)
= (1-0.5)
= 0.5
P2 success rate= (1-failure rate)
= (1-0.4)
= 0.6
Success rate of both P1 and P2 = 0.5 *0.6
= 0.3
Failure rate of both P1 and P2
= 1 – success rate
= 1 – 0.3
= 0.7 (or) 70%
Method-2:
Based upon the failure rate we can find the solution.
Program P is divided into two subprograms.
We can calculate total failure rate by considering the two subprograms
P(P1 U P2)= P1+P2-(P1*P2) /*Check note point */
= (50/100)+(40/100)-(50*40)/100
=90-20
=70%
Note: Failure of P1 + Failure of P2 – (Failure of P1 ∩ Failure of P2)
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