GATE 1987
November 12, 2024Algorithms
November 12, 2024Number-Systems
| Question 46 |
Let A = 1111 1010 and B = 0000 1010 be two 8-bit 2’s complement numbers. Their product in 2’s complement is
| 1100 0100
| |
| 1001 1100
| |
| 1010 0101
| |
| 1101 0101 |
Question 46 Explanation:
A = 1111 1010 = -610 [2’s complement number]
B = 0000 1010 = 1010 [2’s complement number]
A×B = -6×10 = – 6010
⇒ -6010 = 101111002
= 110000112 (1’s complement)
= 110001002 (2’s complement)
B = 0000 1010 = 1010 [2’s complement number]
A×B = -6×10 = – 6010
⇒ -6010 = 101111002
= 110000112 (1’s complement)
= 110001002 (2’s complement)
Correct Answer: A
Question 46 Explanation:
A = 1111 1010 = -610 [2’s complement number]
B = 0000 1010 = 1010 [2’s complement number]
A×B = -6×10 = – 6010
⇒ -6010 = 101111002
= 110000112 (1’s complement)
= 110001002 (2’s complement)
B = 0000 1010 = 1010 [2’s complement number]
A×B = -6×10 = – 6010
⇒ -6010 = 101111002
= 110000112 (1’s complement)
= 110001002 (2’s complement)