Nielit Scientist-B CS 4-12-2016
April 5, 2025Nielit Scientist-B CS 4-12-2016
April 5, 2025Nielit Scientist-B CS 4-12-2016
| Question 4 |
The Circuit is equivalent to:
| Ex-Or | |
| NAND gate | |
| OR gate | |
| AND gate |
Question 4 Explanation:
Step-1: Here, A we are getting A’ and B we are getting B’. So, A’+B’
Step-2: (A’+B’)’=AB
Step-3: (AB)’=A’+B’
Solution: NAND or NOR but in options they are not given NOR. So, Final result is NAND
Step-2: (A’+B’)’=AB
Step-3: (AB)’=A’+B’
Solution: NAND or NOR but in options they are not given NOR. So, Final result is NAND
Correct Answer: B
Question 4 Explanation:
Step-1: Here, A we are getting A’ and B we are getting B’. So, A’+B’
Step-2: (A’+B’)’=AB
Step-3: (AB)’=A’+B’
Solution: NAND or NOR but in options they are not given NOR. So, Final result is NAND
Step-2: (A’+B’)’=AB
Step-3: (AB)’=A’+B’
Solution: NAND or NOR but in options they are not given NOR. So, Final result is NAND