Question 4598 – UGC NET CS 2006 June-Paper-2
March 31, 2024Question 3008 – Research Aptitude
March 31, 2024UGC NET CS 2006 June-Paper-2
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Question 6
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The number of 1 ’s present in the binary representation of (3*512 + 7*64 +5*8 +3) 10 is :
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8
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9
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10
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11
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Question 6 Explanation:
(3*512 + 7*64 +5*8 +3) =2027
(2027) 10 = (111 1110 1011) 2
Here, total number of 1’s are 9.
(2027) 10 = (111 1110 1011) 2
Here, total number of 1’s are 9.
Correct Answer: B
Question 6 Explanation:
(3*512 + 7*64 +5*8 +3) =2027
(2027) 10 = (111 1110 1011) 2
Here, total number of 1’s are 9.
(2027) 10 = (111 1110 1011) 2
Here, total number of 1’s are 9.