JNU PhD CS 2019
October 3, 2023JNU PhD CS 2019
October 3, 2023UGC NET CS 2011 June-Paper-2
| Question 10 |
8-bit 1’s complement form of –77.25 is
| 01001101.0100 | |
| 01001101.0010 | |
| 10110010.1011 | |
| 10110010.1101 |
Question 10 Explanation:
(-77.25)10
Step 1: Convert (77)10into binary form.
Step 1: Convert (77)10into binary form.
Correct Answer: C
Question 10 Explanation:
(-77.25)10
Step 1: Convert (77)10into binary form.
Step 1: Convert (77)10into binary form.