JNU PhD CS 2019
October 3, 2023JNU PhD CS 2019
October 3, 2023UGC NET CS 2011 June-Paper-2
Question 10
|
8-bit 1’s complement form of –77.25 is
01001101.0100
|
|
01001101.0010
|
|
10110010.1011
|
|
10110010.1101
|
Question 10 Explanation:
(-77.25)10
Step 1: Convert (77)10into binary form.


Step 1: Convert (77)10into binary form.


Correct Answer: C
Question 10 Explanation:
(-77.25)10
Step 1: Convert (77)10into binary form.


Step 1: Convert (77)10into binary form.


Subscribe
Login
0 Comments