KVS 30-12-2018 Part B
June 3, 2024COCOMO-Model
June 3, 2024KVS 30-12-2018 Part B
Question 5 |
Represent the decimal number 3.248*104 into a single precision floating point binary number(using standard format).
0|10001101|11111011100000000000000 | |
0|11001101|11111011100000000000000 | |
1|11001101|11111011100000000000000 | |
0|10001110|11111011100000000000000 |
Question 5 Explanation:
Given number is in base 10. Convert it to base-10.
3.248×104 =32480= 1111110111
= 1.111110111 x 214
Mantissa = 11111011100…00
Biased exponent = 14 +127= 141 = 10001101
3.248×104 =32480= 1111110111
= 1.111110111 x 214
Mantissa = 11111011100…00
Biased exponent = 14 +127= 141 = 10001101
Correct Answer: A
Question 5 Explanation:
Given number is in base 10. Convert it to base-10.
3.248×104 =32480= 1111110111
= 1.111110111 x 214
Mantissa = 11111011100…00
Biased exponent = 14 +127= 141 = 10001101
3.248×104 =32480= 1111110111
= 1.111110111 x 214
Mantissa = 11111011100…00
Biased exponent = 14 +127= 141 = 10001101
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