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KVS 30-12-2018 Part B
June 3, 2024
NTA UGC NET Dec 2023 Paper-2
June 3, 2024
KVS 30-12-2018 Part B
June 3, 2024
NTA UGC NET Dec 2023 Paper-2
June 3, 2024

COCOMO-Model

Question 16
A software company needs to develop a project that is estimated as 1000 function points and is planning to use JAVA as the programming language whose approximate lines of code per function point is accepted as 50. Considering a = 1.4 as multiplicative factor, b = 1.0 as exponential factor for the basic COCOMO effort equation and c = 3.0 as multiplicative factor, d = 0.33 as exponential factor for the basic COCOMO duration equation, approximately how long does the project take to complete ?
A
11.2 months
B
12.2 months
C
13.2 months
D
10.2 months
Question 16 Explanation: 
Given data,
— lines of code(LOC)= 50,000 (or 50K)
— Multiplicative value ‘a’=1.4
— Exponential ‘b’=1.0
— Basic COCOMO formula= a*(LOC in K)b
— Multiplicative value ‘c’=3.0
— Exponential ‘d’=0.33
— Development=c*(basic COCOMO result)d
Step-1: Basic COCOMO formula= a*(LOC in K)b
= 1.4*(50)1.0
= 70
Step-2: Development= c*(basic COCOMO result)d
= 3(70)0.33
= 12.18 months
Correct Answer: B
Question 16 Explanation: 
Given data,
— lines of code(LOC)= 50,000 (or 50K)
— Multiplicative value ‘a’=1.4
— Exponential ‘b’=1.0
— Basic COCOMO formula= a*(LOC in K)b
— Multiplicative value ‘c’=3.0
— Exponential ‘d’=0.33
— Development=c*(basic COCOMO result)d
Step-1: Basic COCOMO formula= a*(LOC in K)b
= 1.4*(50)1.0
= 70
Step-2: Development= c*(basic COCOMO result)d
= 3(70)0.33
= 12.18 months
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