Nielit Scientific Assistance CS 15-10-2017

Question 1
A decimal has 25 digits. the number of bits needed for its equivalent binary representation is approximately
A
50
B
74
C
40
D
None of the above
       Digital-Logic-Design       Number-Systems
Question 1 Explanation: 
Consider three digits(1,2,3) of decimal numbers.Maximum number, we can generate by that three digits are 10​ 3​ -1 which is 999.
Then, Decimal number has 25 digits, so maximum number is 10​ 25​ -1
Similarly, in the binary representation with “n” bits the maximum number is 2​ 25​ -1
So we can write 10​ 25​ –1 = 2​ n​ – 1 → 10​ 25​ = 2​ n
After taking log​ 2​ on both sides
log​ 2​ 2​ n​ =log ​ 2​ 10​ 25
n log​ 2​ 2=25 log ​ 2​ 10
n = 25 log ​ 2​ 10
n = 25 x 3.3 [ log​ 2​ 2=1 & log​ 2​ 10 =3.322]
n = 82.5
Note: Original question paper given option D is 60. But actual answer is 82.5.
Question 2
Which of the following is minimum error code?
A
Octal code
B
Binary Code
C
Gray code
D
Excess-3 Code
       Digital-Logic-Design       Number-Systems
Question 2 Explanation: 
→ "Gray code" as an alternative name is "reflected binary code". one of those also lists "minimum error code" and "cyclic permutation code" among the names.
→ Gray codes are widely used to facilitate error correction in digital communications such as digital terrestrial television and some cable TV systems.
Question 3
Match list I with list II and select the correct answer using the codes given below the lists.
A
1 2 3 4
B
3 2 4 1
C
2 3 1 4
D
1 4 2 3
       Computer-Organization       Machine-Instructions
Question 3 Explanation: 
3 address instruction:
Two operand locations and a result location are explicitly contained in the instruction word.
e.g., Y = A − B
2 address instruction:
One of the addresses is used to specify both an operand and the result location.
e.g., Y = Y + X
1 address instruction:
Two addresses are implied in the instruction and accumulator based operations.
e.g., A CC = A CC + X
0 address instructions:
They are applicable to a special memory organization called a stack. It interact with a stack using push and pop operations. All addresses are implied as in register based operations.
T = Tap(T − 1 )
Question 4
A binary search tree contains the values- 1,2,3,4,5,6,7 and 8. The tree is traverses in preorder and the values are printed out. Which of the following sequences is a valid output?
A
5 3 1 2 4 7 8 6
B
5 3 1 2 6 4 9 7
C
5 3 2 4 1 6 7 8
D
5 3 1 2 4 7 6 8
       Data-Structures       Binary-Trees
Question 4 Explanation: 
Preorder traversal yields (Root, left, right)
Option D:
Let draw binary search tree for the given sequence,

After traversing through this tree we will get same sequence.
Question 5
The number of the edges in a regular graph of degree 'd' and 'n' vertices is____
A
Maximum of n,d
B
n+d
C
nd
D
nd/2
       Engineering-Mathematics       Graph-Theory
Question 5 Explanation: 
Sum of degree of vertices = 2*no. of edges
d*n = 2*|E|
∴ |E| = (d*n)/2
Question 6
Consider the following C code segment:
int IsPrime(n)
{
int i,n;
for(i=2;i<=​ √n;i++)
if(n%i == 0)
{
printf(“Not Prime\n”);
return 0;
}
return 1;
}
Let T(n) denotes the number of times the for loop is executed by the program on input n.
Which of the following is TRUE?
A
T(n) = O(​ √n) and T(n) = Ω​ ( √n)
B
T(n) = O(​ √n) and T(n) = ​ Ω ​(1)
C
T(n) = O(n) and T(n) = ​ Ω ​ ( ​ √n)
D
None of the above
       Algorithms       Asymptotic-Complexity
Question 6 Explanation: 
Then the time complexity is Best Case : Ω(1) & Worst Case: O(√n)
Question 7
A language L for which there exists a TM,, 'T', that accepts every word in L and either rejects or loops for every word that is not in L, is said to be
A
recursive
B
recursively enumerable
C
NP-Hard
D
None of the above
       Theory-of-Computation       Recursive-and-Recursively-Enumerable-Language
Question 7 Explanation: 
A language L for which there exists a TM,, 'T', that accepts every word in L and either rejects or loops for every word that is not in L, is said to be recursively enumerable
Question 8
Synthesized attribute can easily be simulated by an
A
LL grammar
B
ambiguous grammar
C
LR grammar
D
none of the above
       Compiler-Design       Syntax-Directed-Translation
Question 8 Explanation: 
● A ​ Synthesized attribute ​ is an attribute of the nonterminal on the left-hand side of a production.
● Synthesized attributes represent information that is being passed up the parse tree.
● LR-attributed grammars allow the attributes to be evaluated on LR parsing. As a result, attribute evaluation in LR-attributed grammars can be incorporated conveniently in bottom-up parsing.
Question 9
The logic of pumping lemma us a good example of
A
The pigeonhole principle
B
The divide and conquer technique
C
recursion
D
Iteration
       Theory-of-Computation       Pumping Lemma
Question 9 Explanation: 
→ The pigeonhole principle is nothing more than the obvious remark: if you have fewer pigeon holes than pigeons and you put every pigeon in a pigeon hole, then there must result at least one pigeon hole with more than one pigeon. It is surprising how useful this can be as a proof strategy.
→ In the theory of formal languages in computability theory, a pumping lemma or pumping argument states that, for a particular language to be a member of a language class, any sufficiently long string in the language contains a section, or sections, that can be removed, or repeated any number of times, with the resulting string remaining in that language. The proofs of these lemmas typically require counting arguments such as the pigeonhole principle.
Question 10
Given relations R(w,x) and S(y,z) the result of SELECT DISTINCT w,x from R<S
A
R has no duplicates and S is non empty
B
R and S have no duplicates
C
S has no duplicates and R is non empty
D
R and S has the same number of tuples
       Database-Management-System       SQL
Question 10 Explanation: 
r has no duplicate, if r can have duplicates it can be remove in the final state. s in non-empty if s is empty then r*s becomes empty.
Question 11
E-R model uses this symbol to represent weak entity set?
A
Dotted rectangle
B
Diamond
C
Doubly outlined rectangle
D
None of these
       Database-Management-System       ER-Model
Question 11 Explanation: 
→ A weak entity is an entity that cannot be uniquely identified by its attributes alone.
→ It must use a foreign key in conjunction with its attributes to create a primary key.
→ The foreign key is typically a primary key of an entity it is related to.
Question 12
By open domain CASE tools we mean
A
tools available in open domain
B
Software packages which can be downloaded from the internet
C
Software packages to aid each phase of the systems analysis and design which an be downloaded free of cost from the internet
D
Source codes of CASE tools
       Software-Engineering       Software-configuration-management
Question 12 Explanation: 
● Tools are also in the open domain which can be downloaded and used.
● They do not usually have very good user interfaces.
Question 13
If P is risk probability, L is loss, then is computed as
A
RE=P/L
B
RE=P+L
C
RE=P*L
D
RE=2*P*L
Question 13 Explanation: 
Risk Exposure(RE) is determined using the following relationship RE = P*L
where P is the probability of occurrence for a risk, and L is the cost to the project should the risk occur.
Question 14
A can is filled with 5 paise coins. Another can is filled with 10 paise coins. Another can is filled with 25 paise coins. All the cans are given wrong labels. If the can labeled 25 paise is not having the 10 paise coins, what will the can, labeled 10 paise have?
A
25 paise
B
5 paise
C
10 paise
D
cannot be determined
       Aptitude       Numerical
Question 14 Explanation: 
A diagram will make it easy to comprehend.

It is easy to find that the can labeled 25 Paise must have 5 paise coins in it. So, the can labeled 10 Paise, must have 25 Paise coins in it.
Question 15
The possible number of boolean function of 3 variables X,Y and Z such that f(X,Y,Z)=f(X',Y',Z')
A
8
B
16
C
64
D
32
       Digital-Logic-Design       Boolean-Function
Question 15 Explanation: 

→ Like above other input combinations also repeat after these inputs.
→ We have 4 input pairs and produces output either 0 or 1.
→ Total functions possible=2*2*2*2 (or) 2​ 4 =16
Question 16
What is the modality of relationship, if there is no explicit need for relationship to occur?
A
0
B
2
C
3
D
1
       Software-Engineering       Modality
Question 16 Explanation: 
→ The modality of a relationship is 0 if there is no explicit need for the relationship to occur or the relationship is optional.
→ The modality is 1 if an occurrence of the relationship is mandatory
Question 17
If the original size of data is 40 then after adding error detection redundancy bit the size of data length is
A
26
B
36
C
46
D
56
       Digital-Logic-Design       Number-Systems
Question 17 Explanation: 
→ Imagine that we want to design a code with m message bits and r check bits that will allow all single errors to be corrected.
→ Each of the 2​ m​ legal messages has n illegal codewords at a distance of 11 from it.
→ These are formed by systematically inverting each of the n bits in the n-bit codeword formed from it. Thus, each of the 2​ m​ legal messages requires n+1 bit patterns dedicated to it.
→ Since the total number of bit patterns is 2​ n​ ,​ We must have (n+1)2​ m​ ≤ 2​ n​ .
→ Using n=m+r, this requirement becomes
= (m+r+1) ≤ 2​ r
= 40+6+1 ≤ 26
= 47 ≤ 2
r=6
Message size will be 6+40=46
Question 18
Bit stuffing refers to
A
Inserting a '0' in user data stream to differentiate it with a flag
B
Inserting a '0' in flag stream to avoid ambiguity
C
Appending a nibble to the flag sequence
D
Appending a nibble to the user data stream
       Computer-Networks       OSI-TCP-layers
Question 18 Explanation: 
● The term "bit stuffing" broadly refers to a technique whereby extra bits are added to a data stream, which do not themselves carry any information, but either assist in management of the communications or deal with other issues.
● The receiver knows how to detect and remove or disregard the stuffed bits.
Question 19
A microprogrammed control unit
A
Is faster than a hardwired unit
B
Facilitates easy implementation of a new instruction
C
Is useful when small programs are to be run
D
All of the above
       Computer-Organization       Microprogrammed-Control-Unit
Question 19 Explanation: 
→ In hardwired control, we saw how all the control signals required inside the CPU can be generated using a state counter and a PLA circuit.
→ There is an alternative approach by which the control signals required inside the CPU can be generated . This alternative approach is known as microprogrammed control unit.
→ In microprogrammed control unit, the logic of the control unit is specified by a microprogram. A microprogram consists of a sequence of instructions in a microprogramming language. These are instructions that specify microoperations.
→ A microprogrammed control unit is a relatively simple logic circuit that is capable of
(1) sequencing through microinstructions.
(2) generating control signals to execute each microinstruction.
→ The concept of microprogram is similar to computer program. In computer program the complete instructions of the program is stored in main memory and during execution it fetches the instructions from main memory one after another.
→ The sequence of instruction fetch is controlled by program counter (PC)
Question 20
If the channel is band limited to 6 kHz and signal to noise ratio is 16, what would be the capacity of channel?
A
16.15kbps
B
23.24 kbps
C
40.12 kbps
D
24.74 kbps
       Electronics       Data-Communication
Question 20 Explanation: 
→ Shannon Capacity (Noisy Channel) In presence of Gaussian band-limited white noise, Shannon-Hartley theorem gives the maximum data rate capacity.
C=B log​ 2​ (1+S/N).
where S and N are the signal and noise power, respectively, at the output of the channel.
→ This theorem gives an upper bound of the data rate which can be reliably transmitted over a thermal-noise limited channel. =6 * log​ 2​ (1+16)
=6 * 4.08746284125034
=24.74 kbps
Question 21
At 100% modulation, the power in each sideband is__ of that of arrier.
A
50%
B
40%
C
60%
D
25%
       Electronics       Data-Communication
Question 21 Explanation: 
→ Power in sidebands may be calculated as modulation index.
→ Each sideband is 25%. Total modulation index=1.
Question 22
The capacity relationship is given by
A
C=Wlog​ 2​ (1+S/N)
B
C=2Wlog​ 2​ (1+S/N)
C
C=Wlog​ 2​ (1-S/N)
D
C=Wlog​ 10​ (1+S/N)
       Electronics       Data-Communication
Question 22 Explanation: 
→ Shannon Capacity (Noisy Channel) In presence of Gaussian band-limited white noise, Shannon-Hartley theorem gives the maximum data rate capacity.
C=W log​ 2​ (1+S/N).
where S and N are the signal and noise power, respectively, at the output of the channel.
→ This theorem gives an upper bound of the data rate which can be reliably transmitted over a thermal-noise limited channel.
Question 23
Which of the following algorithm solve the all pair shortest path problem?
A) Dijkstra's algorithm
B) Floyd's algorithm
C) prim's algorithm
D) Warshall's algorithm
A
Both A and B
B
Both A and C
C
Both C and D
D
Both B and D
       Algorithms       Dynamic-Programming
Question 23 Explanation: 
The Floyd Warshall Algorithm is for solving the All Pairs Shortest Path problem. The problem is to find shortest distances between every pair of vertices in edge weighted directed Graph.
Question 24
An algorithm is made up of two modules M1 and M2. If order of M1 is f(n) and M2 is g(n) then the order of algorithm is
A
max(f(n),g(n))
B
min(f(n),g(n))
C
f(n)+g(n)
D
f(n) * g(n)
       Algorithms       Asymptotic-Complexity
Question 24 Explanation: 
In this problem, we have to check all possibilities.


So, we will prefer max(f(n),g(n)).
Question 25
Choose the correct statements
A
A total recursive function is also a partial recursive function
B
A partial recursive function is also a total recursive function
C
A partial recursive function is also a primitive recursive function
D
None of the above
       Database-Management-System       ER-Model
Question 25 Explanation: 
→ Primitive recursive functions are a class of functions that are defined using composition and primitive recursion
→ They are a strict subset of those μ-recursive functions (also called partial recursive functions) which are also total functions.
→ Primitive recursive functions form an important building block on the way to a full formalization of computability.
→ A total recursive function is also a partial recursive function
Question 26
Assume transaction A holds a shared lock R. If transaction B also requests for a shared lock on R. It will
A
result in deadlock situation
B
immediately be granted
C
immediately be rejected
D
be granted as soon as it is released by A
       Database-Management-System       Transactions
Question 26 Explanation: 
● Shared locks exist when two transactions are granted read access.
● One transaction gets the shared lock on data and when the second transaction requests the same data it is also given a shared lock.
● Both transactions are in a read-only mode, updating the data is not allowed until the shared lock is released.
● There is no conflict with the shared lock because nothing is being updated.
● Shared locks last as long as they need to last; it depends on the level of the transaction that holds the lock.
Question 27
Disk requests come to a disk driver for cylinders in the order 10, 22, 20, 2, 40, 6 and 38 at a given time when the given disk drive is reading from cylinder 20. The seek time is 6ms per cylinder.What is the total seek time, if the disk arm scheduling algorithm FCFS is used?
A
900 ms
B
850 ms
C
360 ms
D
876 ms
       Operating-Systems       Disk-Scheduling
Question 27 Explanation: 

Total seek time= 10+12+2+18+38+34+32
= 146*6 ms
= 876 ms
Question 28
Table Employee has 10 records. It has a non-NULL SALARY column which is also
UNIQUE. The SQL statement
SELECT COUNT(*) FROM Employee WHERE SALARY > ANY (SELECT SALARY FROM EMPLOYEE);
A
10
B
9
C
5
D
0
       Database-Management-System       SQL
Question 28 Explanation: 
This query counts the number of employees who get more than the minimum salary. From the 10 employees, you need to exclude all those employees who are getting the minimum salary. Since the SALARY column is UNIQUE, only one employee will be getting the minimum salary.
Question 29
Which level of RAID refers to disk mirroring with block striping?
A
RAID level 1
B
RAID level 2
C
RAID level 0
D
RAID level 3
       Computer-Organization       RAID
Question 29 Explanation: 
RAID is a technology that is used to increase the performance and/or reliability of data storage.
Following are the various RAID levels:
RAID 0: Stripping
RAID 1: Mirroring
RAID 2: Hamming code for error detection
RAID 3: Byte-level striping with a dedicated parity disk
RAID 4: Block-level striping with block-level striping with two parity blocks parity
RAID 5: Block-level striping with distributed parity
RAID 6: Block-level striping with double distributed parity.
Question 30
Which of the following is not a form of main memory?
A
Instruction cache
B
Instruction register
C
Instruction Opcode
D
Translation lookaside buffer
       Computer-Organization       Machine-Instructions
Question 30 Explanation: 
→ The instruction opcode is the portion of a machine language instruction that specifies the operation to be performed. Beside the opcode itself, most instructions also specify the data they will process, in the form of operands. In addition to opcodes used in the instruction set architectures of various CPUs, which are hardware devices, they can also be used in abstract computing machines as part of their byte code specifications.
Question 31
The following program fragment prints
int i=5;
do
{
putchar(i+100);
printf("%d",i--);
}while(i);
A
i5h4g3f2el
B
14h3g2f1e0
C
An error message
D
None of the above
       Programming       Control Flow
Question 31 Explanation: 
Step-1: putchar(105) will print the ASCII equivalent of 105 is ' i '.
Step-2: The printf statement prints the current value of i=5 because we are given post decrement.
Step-3: The same process will perform until it fail the condition.
Question 32
The running time of an algorithm T(n),where 'n' is the input size, is given by
T(n)=8T(n/2)+qn, if n>1
=p, if n=1
Where p,q are constants. The order of this algorithm is
A
n​ 2
B
n​ n
C
n​ 3
D
N
       Algorithms       Recurrences
Question 32 Explanation: 
The above recurrence is in the form of masters theorem.
Case-1: a>bk
Here, a=8,b=2,k=1,p=0
O(n(log​ 2​ 8))=O(n(log​ 2​ 2​ 3​ ))=O(n​ 3​ (log​ 2​ 2)) [ log​ 2​ 2=1]
=O(n​ 3​ )
Question 33
The convergence of the bisection method is
A
Cubic
B
Quadratic
C
Linear
D
none
       Engineering-Mathematics       Convergence-Bisection
Question 33 Explanation: 
The convergence of the bisection method is very slow. Although the error, in general, does not decrease monotonically, the average rate of convergence is 1/2 and so, slightly changing the definition of order of convergence, it is possible to say that the method converges linearly with rate 1/2.
Note:For the bisection you simply have that ε​ i+1​ /ε​ i​ =1/2, so, by definition the order of convergence is 1 (linearly).
Question 34
When transaction T​ i​ requests a data item currently held by T​ j​ , T​ j​ is allowed to wait only if it has a timestamp smaller than that of T​ j​ (that is, T​ i​ older than T​ j​ ). Otherwise, T​ i​ is rolled back(dies). this is
A
Wait-die
B
Wait-wound
C
Wound-Wait
D
Wait
       Database-Management-System       Transactions
Question 34 Explanation: 
Wait-die scheme​ :
It is a non-preemptive technique for deadlock prevention. When transaction T​ i​ requests a data item currently held by T​ j​ , T​ i​ is allowed to wait only if it has a timestamp smaller than that of T​ j​ (That is T​ i​ is older than T​ j​ ), otherwise T​ i​ is rolled back (dies).
→ In this scheme, if a transaction requests to lock a resource (data item), which is already held with a conflicting lock by another transaction, then one of the two possibilities may occur
1. If TS(T​ i​ ) < TS(T​ j​ ) − that is T​ i​ , which is requesting a conflicting lock, is older than T​ j −then Ti is allowed to wait until the data-item is available.
2. If TS(T​ i​ ) > TS(T​ j​ ) − that is T​ i​ is younger than T​ j​ − then T​ i​ dies. T​ i​ is restarted later with a random delay but with the same timestamp.
→ This scheme allows the older transaction to wait but kills the younger one.
Example:
Suppose that transaction T22, T23, T24 have time-stamps 5, 10 and 15 respectively. If T22 requests a data item held by T23 then T22 will wait. If T24 requests a data item held by T23, then T24 will be rolled back.
Question 35
What will be the output of following?
main()
{
static int a=3;
printf("%d",a--);
if(a)
main();
}
A
3
B
3 2 1
C
3 3 3
D
Program will fall in continuous loop and print 3
       Programming-for-Output-Problems       Storage-Classes
Question 35 Explanation: 
Step-1: initial a=3 but we are given storage class is static.
Step-2: In printf( ) we are given post decrement. So, it will print 3 then decrements.
Step-3: if(2) then we are calling main() function, a=2 because of static otherwise it will be 3 only.
Step-4: It will print 2 and next iteration will print 1.
Question 36
Web links are stored within the page itself and when you wish to 'jump' to the page that is linked, we select the hotspot or anchor. This technique is called
A
Hypertext
B
hypermedia
C
Both (A) and (B)
D
Anchoring
       Web-Technologies       HTML
Question 36 Explanation: 
Web links are stored within the page itself and when you wish to 'jump' to the page that is linked, we select the hotspot or anchor. This technique is called hypertext (or) Hypermedia
Question 37
Twelve 1 ​ Ω ​ resistances are used as edges to form a cube. The resistance between two diagonally opposite corners of the cube is
A
5/6 ​ Ω
B
1/6 ​ Ω
C
6/5 ​ Ω
D
3/2 ​ Ω
       Electronics       Data-Communication
Question 37 Explanation: 
Question 38
The final value theorem is used to find the
A
Steady state value of the system output
B
Initial value of the system output
C
Transient behaviour of the system output
D
None of these
       Electronics       Data-Communication
Question 38 Explanation: 
The final value theorem is used to find the steady state value of the system output
Question 39
For the discrete signal x[n]=a​ n​ u[n], a>0 the z-transform is
A
(z+a)/z
B
(z-a)/z
C
z/(z-a)
D
z/(z+a)
       Electronics       Data-Communication
Question 39 Explanation: 
Let x[n] be causal signal given by x[n] = a​ n​ u[n]
→ The Z-Transform of x[n] is given by

The ROC is defined by | az −1 | < 1 or | z| > | a| .
Region of Convergence(RoC)
Region of Convergence for a discrete time signal x[n] is dened as a continuous region in z plane where the Z-Transform converges. In order to determine RoC, it is convenient to represent the Z-Transform as a is rational X(z)=P(z)/Q(z)
1. The roots of the equation P(z) = 0 correspond to the ’zeros’ of X(z)
2. The roots of the equation Q(z) = 0 correspond to the ’poles’ of X(z)
3. The RoC of the Z-transform depends on the convergence of the polynomials P(z) and Q(z).
Question 40
​ For a periodic signal v(t)=30 sin 100t+10cos 300t +6 sin (500t + ​ π ​ /4), the fundamental frequency in rad/s
A
100
B
300
C
500
D
None of the above
       Electronics       Data-Communication
Question 40 Explanation: 
Given, the signal
V (t) = 3 0 sin 100t + 10 cos 300t + 6 sin (500t + π/4)
So, we have
ω 1 = 100 rads
ω 2 = 300 rads
ω 3 = 500 rads
∴ The respective time periods are
T 1 = 2π/ω1 = 2π/100 sec
T 2 = 2π/ω2 = 2π/300 sec
T 3 = 2π/ω3 = 2π/500 sec
So, the fundamental time period of the signal is
LCM (T 1 , T 2 , T 3 ) =LCM (2π,2π,2π)/HCF (100,300,500)
as T 0 =2π/100
∴ The fundamental frequency, ω0 =2π/T 0 = 100 rad/s
Question 41
​ If the number of bits per sample in a PCM system is increased from a n to n+1, the improvement in signal to quantization noise ratio will be
A
3dB
B
6db
C
2n dB
D
n dB
       Electronics       Data-Communication
Question 41 Explanation: 
(S/N q)dB
= (1.76 + 6 n) dB
(SQNR) 1 = 1 .76 + 6 n
(SQNR) 2 = 1 .76 + 6 n(n + 1 ) = 1 .76 + 6 n + 6
(SQNR) 2 − (SQNR) 1 = 1 .76 + 6 n + 6 − 1 .76 − 6 n = 6 dB
So for every one bit increase in bits per sample will result is 6 dB improvement in signal to quantization ratio.
Question 42
A carrier A​ c​ Cos(w​ C​ )t is frequency modulated by a signal E​ m​ Cos(w​ m​ )t. The modulation index is m​ f​ . the expression for the resulting FM signal is
A
A​ c,​ Cos[w​ c​ t+ m​ f​ Sin(w​ m​ )t]
B
A​ c​ Cos[w​ c​ t+ m​ f​ Cos(w​ m​ )t]
C
A​ c​ Cos[w​ c​ t+ ​ π ​ m​ f​ Sin w​ m​ t]
D
A​ c​ Cos[w​ c​ t+ 2 ​ π ​ m​ f​ E​ m​ Cos(w​ m​ )t/w​ m​ ]
       Electronics       Data-Communication
Question 42 Explanation: 
Question 43
A sequential circuit using D flip flop and logic gates is shown in figure, Where X and Y are the inputs and Z is the output. The circuit is
A
S-R flip flop with inputs X=R and Y=S
B
S-R flip flop with inputs X=S and Y=R
C
J-K flip flop with inputs X=J and Y=K
D
J-K flip flop with X=k and Y=J
       Digital-Logic-Design       Sequential-Circuits
Question 43 Explanation: 
Here, PI=Present Input
PS=Present state
NS=Next State
Q​ n+1​ =D=f(PI,PS)=f(x,y,Q​ n​ )
D=X’Z+YZ

Question 44
A 4 bit ripple counter and a 4 bit synchronous counter are made using flip flops having a propagation delay of 10ns each. If the worst case delay in the ripple counter and the synchronous counter be R and S respectively, then
A
R=10 ns, S=40ns
B
R=40ns, S=10ns
C
R=10ns, S=30ns
D
R=30 ns, S=10ns
       Digital-Logic-Design       Sequential-Circuits
Question 44 Explanation: 
→ In synchronous counter time delay is constant while in Ripple it is additive.
→ In Ripple counter (or) Asynchronous counter each flip flop waits for its previous flip flops output.
R= bit size*propagation delay
= 4*10ns
= 40ns
→ In Synchronous counter all flip flops are triggered by same clock. It will gives output of all four flip flops at the same time.
S=10ns
Question 45
In MOSFET fabrication, the channel length is delayed during the process of
A
Isolation oxide growth
B
Channel stop implantation
C
Poly-Silicon gate patterning
D
Lithography step leading to the contact pad
       Data-Communication       MOSFET
Question 45 Explanation: 
In MOSFET fabrication channel length is defined during Poly-Silicon gate patterning process
Question 46
The open loop transfer function of a feedback control system is G(s).H(s)=1/(S+1)​ 3​ . The gain margin of the system is
A
2
B
4
C
8
D
16
       Electronics       Data-Communication
Question 46 Explanation: 
Given data,
The open loop transfer function of a feedback control system is G(s).H(s)=1/(S+1)​ 3
Gain margin=?
→ Here, the formula is -3tan​ -1​ (W​ pc​ ) = -180​ 0
tan​ -1​ (W​ pc​ ) = -180​ 0​ /3
= -60​ 0
W​ pc​ =√3 rad/sec
G(s).H(s)=1/(S+1)​ 3
|G(s).H(s)|=X= 1/(1+W​ pc2​ )
=1⁄8
G(s).H(s)=1/X
= 8
Question 47
​ An ideal op-amp is an ideal
A
Voltage controlled current source
B
voltage controlled voltage source
C
current controlled current source
D
current controlled voltage source
       Electronics       Data-Communication
Question 47 Explanation: 
An ideal op-amp lead us to an op-amp with input resistance is infinite, so no current flows into either input terminal (the “current rule”) and that the differential input offset voltage is zero (the “voltage rule”).
Ideal operational amplification will have
➝ High input impedance ( R in = ∞ ) and low output impedance ( R out = 0 )

➝ R in = ∞ , so zero input current
➝ Infinite voltage gain
➝ So, it is a voltage controlled voltage source device.
Question 48
In a ripple counter using edge-triggered JK flip-flops, the pulse input is applied to
A
Clock input of all flip flops
B
j and K input of one flip flop
C
J and K input of all flip flops
D
Clock input of one flip flops
       Digital-Logic-Design       Sequential-Circuits
Question 48 Explanation: 
A ripple counter is an asynchronous counter where only the first flip-flop is clocked by an external clock.
→ All subsequent flip-flops are clocked by the output of the preceding flip-flop. Asynchronous counters are also called ripple-counters because of the way the clock pulse ripples it way through the flip-flops.

So, answer is clock input of one flip-flop.
Question 49
If a processor has 32 bit virtual address, 28 bit physical address, 2 KB pages. How many bits are required for the virtual,physical page number?
A
17,21
B
21,17
C
6,10
D
None
       Operating-Systems       Virtual Memory
Question 49 Explanation: 
Number of entries for virtual page number = 2​ virtual address​ / Pages =2​ 32​ /2KB= 2​ 32​ /2​ 11​ =2​ 21
Number of entries for physical page number = 2​ physical address​ / Pages =2​ 28​ /2KB= 2​ 28​ /2​ 11​ =2​ 17
The number bits for virtual page number are 21.
The number bits for physical page number are 21.
Question 50
What is the maximum value of the function f(x)=2x​ 2​ -2x +6 in the interval [0,2]?
A
6
B
10
C
12
D
5,5
       Engineering-Mathematics       Calculus
Question 50 Explanation: 
An open interval does not include its endpoints, and is indicated with parentheses. For example, (0,1) means greater than 0 and less than 1.
A closed interval is an interval which includes all its limit points, and is denoted with square brackets. For example, [0,1] means greater than or equal to 0 and less than or equal to 1.
A half-open interval includes only one of its endpoints, and is denoted by mixing the notations for open and closed intervals. (0,1] means greater than 0 and less than or equal to 1, while [0,1) means greater than or equal to 0 and less than 1.
Given function f(x)=2x​ 2​ -2x +6 and the given interval is [0,2]
According to the given interval , we need to check the function at the values 0,1,2.
f(0)=2x0-2x0+6=6
f(1)=2x1​ 2​ -2x1+6=2-2+6=6
f(2)=2x2​ 2​ -2x2+6=8-4+6=10
Question 51
The value of the integral
A
(x+2)/2
B
2/(π-2)
C
π-2
D
π+2
       Engineering-Mathematics       Calculus
Question 51 Explanation: 
The integral value of x​ 2​ sin(x)dx is [−x​ 2​ cos(x)+2xsin(x)+2cos(x)+C]​ with the interval [π/2,0]
=[−(​ π/2)​ 2​ cos(​ π/2​ )+2​ π/2​ sin(​ π/2​ )+2cos(​ π/2​ )+C]​ - ​ [−(​ 0)​ 2​ cos(​ π/2​ )+2(0)sin(​ π/2​ )+2cos(​ 0 ​ )+C]
=[0+​ π+0+C-2-C]
=π-2
Question 52
Which of the following would not be specified in a communication protocol?
A
Header contents
B
Trailer contents
C
Error Checking
D
Data content of message
       Computer-Networks       Communication-protocol
Question 52 Explanation: 
→ A communication protocol is a system of rules that allow two or more entities of a communications system to transmit information via any kind of variation of a physical quantity. The protocol defines the rules, syntax, semantics and synchronization of communication and possible error recovery methods.
→ There are many properties of a transmission that a protocol can define. Common ones include: packet size, transmission speed, error correction types, handshaking and synchronization techniques, address mapping, acknowledgement processes, flow control, packet sequence controls, routing, address formatting
Question 53
Which of the definitions generates the same languages as L, where
L={ x​ n​ y​ n​ , n>=1 }
i. E→ xEy |xy
ii.xy|x​ +​ x yy​ +
iii. x​ +​ y​ +
A
i only
B
i and ii only
C
ii and iii only
D
ii only
       Theory-of-Computation       Languages-and-Grammars
Question 53 Explanation: 
The language L={ x​ n​ y​ n​ , n>=1 }
For n=1, xy
n=2,x​ 2​ y​ 2
n=3,x​ 3​ y​ 3
In the above language , there are equal number of x’s followed by y’s
Definition-1​ :E→ xEy |xy → xEy → xxEyy → xxxEyyy → xxxxyyyy
Which is nothing but equal number of x’s followed by equal number of y’s
X​
+​
means one or more x’s
Y​
+
​ means one or more y’s
Definition -2 : The expression xy|x​ +​ x yy​ + ​ gives xy, xxyy , xxxxyy , xxyyyyy and so on
The definition-2 won’t give equal number of x’s followed by y’s
It generates any number of x’s followed by any number of y’s.
Definition -3 :
The expression x​ +​ y​ +​ gives xy, xxy,xxxy,xyy,xyyy and so on strings.
The definition-3 won’t give equal number of x’s followed by y’s
It generates any number of x’s followed by any number of y’s.
Question 54
Which of the following is a desirable property of module?
A
Independency
B
Low Cohesiveness
C
High Coupling
D
Multifunctional
       Software-Engineering       Coupling-and-Cohesion
Question 54 Explanation: 
● Highly coupled have program units dependent on each other.
● Loosely coupled are made up of units that are independent or almost independent.
● The desirable property is High cohesion and low coupling
● From the above options , the suitable option is independency
Question 55
The solution of the recurrence relation a​ r​ =a​ r-1​ +2a​ r-2​ with a​ 0​ =2,a​ 1​ =7
A
a​ r​ =(3)​ r​ +(1)​ r
B
2a​ r​ =(2)​ r​ /3 -(1)​ r
C
a​ r​ =3​ r+1​ -(-1)​ r
D
a​ r​ =3(2)​ r​ -(-1)​ r
       Engineering-Mathematics       Combinatorics
Question 55 Explanation: 
● Given the recurrence relation a​ r​ =a​ r-1​ +2a​ r-2 and a​ 0​ =2,a​ 1​ =7.
● For r =2, a​ 2=​ a​ 2-1​ +2a​ 2-2​ =a​ 1​ +2a​ 0​ =7+2*2=7+4=11 ● For r=3,a​ 3=​ a​ 3-1​ +2a​ 3-2​ =a​ 2​ +2a​ 1​ =11+2*7=11+14=25
● From the above options ,Substitute the r values 0,1,2,3 then option -D gives the solution to recurrence relation.
Question 56
M is a square matrix of order 'n' and its determinant value is 5. If all the elements of M are multiplied by 2, Its determinant value becomes 40. The value of 'n' is
A
2
B
3
C
5
D
4
       Engineering-Mathematics       Linear-Algebra
Question 56 Explanation: 
● From the matrix property : If each element of a row (or a column) of a determinant is multiplied by a constant k, then its value gets multiplied by k.
● Consider matrix order is 3, there are 3 rows and each row is multiplied by 2 means we need to multiply 8 to the existing determinant.
● The given existing determinant is 5 and each row multiplied by 2 means 8 *5 =40.
Question 57
The question is based on the following program fragment.
f(int Y[10], int x)
{
int u,j,k;
i=0;j=9;
do
{
k=(i+j)/2;
if(Y[k] i=k;
else
j=k;
}while((Y[k]!=x) && (i if(Y[k] ==x)
printf("x is in the array");
else
printf("x is not in the array");
}
On which of the following contents of 'Y' and 'x' does the program fail?
A
Y is [1 2 3 4 5 6 7 8 9 10] and x<10
B
Y is [1 3 5 7 9 11 13 15 17 19] and x<1
C
Y is [ 2 2 2 2 2 2 2 2 2 2] and x>2
D
Y is [ 2 4 6 8 10 12 14 16 18 20] and 2
       Algorithms       Searching
Question 57 Explanation: 
This above code is similar to binary search
First iteration:
I=0,j=9
K=(0+9)/2=4
Elements with duplicate values of “2” the condition if(Y[k] Second iteration :
I=0, j=k=4
K= (0+4)/2=2.
Third iteration:
I=0, j=k=2
K= (0+2)/2=1
Fourth iteration:
I=0, j=k=1
K= (0+1)/2=0
The while condition is Y[k] != x && i < j is true
→ The above program doesn’t work for the cases where element to be searched is the last element of Y[ ] or greater than the last element (or maximum element) in Y[ ].
→ For such cases, program goes in an infinite loop because i is assigned value as k in all iterations, and i never becomes equal to or greater than j.
So, while condition never becomes false.
Question 58
The address sequence generated by tracing a particular program executing in a pure demand paging system with 100 records per page, with 1 free main memory frame is recorded as follows. 0100, 0200, 0430, 0499, 0510, 0530, 0560, 0120, 0220, 0240, 0260, 0320, 0370, What is the number of page faults?
A
15,4
B
6,4
C
7,2
D
4,6
       Operating-Systems       Page-Replacement-algorithm
Question 58 Explanation: 
Memory page numbers will be calculated by using corresponding to given address as follows
The page number is 1 from the record numbers 1-100,
The page number is 2 from the record numbers 101 -200
The page number is 3 from the record numbers 201 -300
The page number is 4 from the record numbers 301 -400
The page number is 5 from the record numbers 401 -500
The page number is 6 from the record numbers 501 -600
The page number is 7 from the record numbers 601 -700
For a given address sequence 0100, 0200, 0430, 0499, 0510, 0530, 0560, 0120, 0220, 0240,0260, 0320, 0370
The page number numbers sequence is 1,2,5,5,6,6,6,2,3,3,3,4,4
The number of available frame is 1, So we need to use only one frame for executing demand page process.

So total number of page faults are 7.
Question 59
Consider an ε-tree CFG. If for every pair of productions A → u and A → v
A
if FIRST(u) ∩ FIRST(v) is empty then the CFG has to be LL(1)
B
If the CFG is LL(1) then FIRST(u) ∩ FIRST(v) has to be empty
C
Both (A) and (B)
D
None of the above
       Compiler-Design       Parsers
Question 59 Explanation: 
The condition for a grammar to be LL(1)
Theorem: A context free grammar G=(V​ T​ , V​ N​ , S,P) is LL(1) if and if only if for every nonterminal A and every strings of symbols ⍺,β such that ⍺≠β and A → ⍺,β we have
1. First(⍺) ∩ First (β) ∩ Follow(A)=Θ.
2. If ⍺ *⇒ ε then First(β) ∩ Follow(A)= Θ.
If grammar is epsilon free then condition 2 is not required.
Now as per condition 1, for every non-terminal A, if we have A → u and A→v
And First(u) First(v) = φ and CFG is epsilon free then it must be LL(1) and if epsilon free CFG is LL(1) then it must satisfy the condition 1.
Question 60
A solution for the differential equation x'(t) + 2x(t) =​ δ ​ (t) with initial condition x(~0)=0
A
e​ -2t​ u(t)
B
e​ 2t​ u(t)
C
e​ -t​ u(t)
D
e​ t​ u(t)
       Electronics       Data-Communication
There are 60 questions to complete.

Scientific Assistance CS 15-10-2017

Question 1
The difference between the compound interest and the simple earned at the end of 3​ rd​ year on a sum of money at a rate of 10% per annul is Rs. 77.5. What is the sum?
A
Rs. 3,500
B
Rs. 2,500
C
Rs. 3,000
D
Rs. 2,000
Question 1 Explanation: 
Let principal be ‘x’
S.I = P T R / 100
S.I = X * 3 * 10 / 100
C.I = [ P (1 + (R / 100)T) - P]
C.I = [ X (1+ (10 / 100)3) - X]
C.I = 331X / 1000
Difference between Compound interest and Simple interest is 77.5
( 331X / 1000 ) - ( 3X / 10) = 77.5
31x / 1000 = 77.5
x = 2500.
Question 2
Aamir and Birju can cut 5000g of wood in 20 min. Birju and Charles can cut 5000g of wood in 40 min. Charles and Aamir cut 5 kg of wood in 30 min. How much time Charles will take to cut 5 kg wood alone?
A
120 min
B
48 min
C
240 min
D
120 min
Question 2 Explanation: 
Here in this question 5000g means 5kg only
So from that question Aamir (A) Birju (B) Charles (C)
Let Aamir, Birju and Charles alone can complete the work in A, B and C minutes respectively, then
1 min. work of (A+B)=1/20, (B+C)=1/40 and (C+A)=1/30
A + B + C = 13/240
1 min. work of C = (A+B+C) - (A+B) = 13/240 - 1/20 = 1/240
So C alone can complete the work in 240 min.
Question 3
An alloy contains copper and zinc in the ratio 5 : 3 and another contains copper and tin in the ratio 8 : 5, If equal weights of the two are melted together to form a 3​ rd​ alloy, find the weight of tin per kg in the new alloy.
A
40/129
B
5/13
C
5/26
D
28/5
Question 3 Explanation: 
Amount of copper in first alloy is 5x/8 and zinc is 3x/8.
Amount of copper in second alloy is 8x/13 and tin is 5x/13.
So after mixing tin is available in 2 alloy only that means in 3rd alloy 5x/13/2x
Tin present in 3rd alloy is 5/26.
Question 4
X is a whole number. If the only common factors of X and X2 are 1 and X, then X is _______
A
1
B
a perfect square
C
an odd number
D
a prime number
Question 4 Explanation: 
A number that is divisible only by itself and 1 is called prime number.
Question 5
Line AB is 24 metres in length and tangent to the inner one of the two concentric circles at point C, Points A and B lie on the circumference of the outer circle. It is known that the radii of the two circles are integers. The radius of the outer circle is
A
13m
B
5 m
C
7 m
D
4m
Question 5 Explanation: 

Given data,
AB=24cm
CB=12cm
θC=5cm(Assume)
θB=5​ 2​ +12​ 2​ =169
θB=13cm
Note: They forgot to mention the value 5. If we are considering value=5 then answer should be A.
Question 6
Monisha is working with a real estate agent to find a location for the kids’ toy store she plans to open in her town. She is looking for a place that is either in the centre or not too far from the centre of town. It should also be attractive for the right kind of footfall too. Which of the following locations should Monisha’s agent call to her attention?
A
a storefront in a new high-rise building near the train station in the center of town whose occupants are mainly young, childless professionals who use the train to commute to their offices each day
B
a little shop three blocks away from the town’s main street, located across the street from an elementary school and next door to an ice cream store
C
a stand-alone storefront on a quiet residential street ten blocks away from the town’s center
D
a storefront in a small a strip mall located on the outskirts of town that is also occupied by a pharmacy and a dry cleaner
Question 6 Explanation: 
This option is both near the center of town and in a location where children and their parents are sure to be around. This is the only option that meets both of Monisha’s requirements.
Question 7
Reading is a psycholinguistic guessing game. To read critically is a skill as it is a demanding process. One must slow down one’s reading and, with a pencil in hand, perform specific operations on the text. Mark up the text with reactions, conclusions and questions. When one reads, one becomes an active participant.
A
critical reading is a slow, dull, but essential process.
B
the best critical reading happens at critical times in a person’s life.
C
readers should get in the habit of questioning the truth of what they read.
D
critical reading requires thoughtful and careful attention
Question 7 Explanation: 
Option-A FALSE: The author never says that reading is dull.
Option-B,C FALSE: Not related to given paragraph.
Option-D TRUE: The author stresses the need to read critically by performing thoughtful and careful operations on the text.
Question 8
Find the missing term:
60, 40, 55, 45, 50, 50,?
A
45
B
50
C
55
D
60
Question 8 Explanation: 
Question 9
Find the missing alphabet:
T, r, O, m, J,?
A
h
B
i
C
I
D
g
Question 9 Explanation: 
In between r and T there is letter is s
Likewise m and O letter is n
Same h is the next letter to fit in that sequence
Question 10
Here are some words translated from an artificial language.
Qmelaqali means fruitcake
Qalitiimmeo means cakewalk
Useguamao means buttercup
Which word could mean “cupcake”?
A
qalitiiqali
B
amaotiimmeo
C
pakitreft
D
amaoqali
Question 10 Explanation: 
Qmelaqali→ fruitcake
We can divide artificial language into parts.
Qmela→ fruit
qali→ cake
Qalitiimmeo→ cakewalk
We can divide artificial language into parts.
Qali→ cake
tiimmeo→ walk
Useguamao → buttercup
We can divide artificial language into parts.
Usegu→ butter
amao→ cup
cupcake→ ?
amao→ cup
qali→ cake
So, option-D is correct answer.
Question 11
A man walks 5 Km towards south and then turns to the right. After walking 3 Km he turns to the left and walks 5 Km. Now in which direction is he from the starting place?
A
West
B
South
C
North-East
D
South- West
Question 11 Explanation: 
Question 12
If the consonants in the word ‘DROVE’ are first arranged alphabetically and the vowels are put in between two pairs of consonants in the alphabetical order, which of the following will be the fourth from the right end after the rearrangement?
A
D
B
E
C
R
D
O
Question 12 Explanation: 
In the word DROVE we have two vowels
Those are O and E
After consonants are arranged in alphabetically we got the word like DRV
But we have two place vowels in between two pairs of consonants we got finally DEROV
So right from fourth letter is E
Question 13
There is a queue in a ticketing office. Amanda is 10​ th​ from the front while Murthy is 25​ th from behind and Marta is just in the middle of the two. If there be 50 persons in the queue. What position does Marta occupy from the front?
A
16
B
18
C
15
D
17
Question 13 Explanation: 
Question 14
There are five janitors. Pali, Qureshi, Rohan, Sant and Timber. They all have a different height, Qureshi is shorter than only Timber and Sant is shorter than Pali and Qureshi. Who among them is the shortest?
A
Rohan
B
Sant
C
Pali
D
Data inadequate
Question 14 Explanation: 
From that question we can decide Pali Quereshi sant and timber but Rohan is not mentioned there. So Data inadequate is answer.
Question 15
A $ B means A is the father of B; A # B means A is the sister of B; A * B means A is the daughter of B and A @ B means A is the brother of B. Which of the following indicates that M is the wife of Q?
A
Q $ R # T @ M
B
Q $ R @ T # M
C
Q $ R * T # M
D
Q $ R @ T * M
Question 15 Explanation: 
Q $ R means R’s father is Q
R @ T means T’s brother is R
T * M means M’s Daughter T
Finally M’s Daughter is T and T’s Brother is R and R’s father is Q so Q’s wife is M.
Question 16
Count the number of squares in the given figure.
A
32
B
30
C
29
D
28
Question 16 Explanation: 
For this type of questions there is one formula that is
[ n (n+1)(2n+1) ] / 6
Here n is 4 because it’s 4 x 4
[ 4 (4+1)(8+1) ] / 6
30
Question 17
Who was the Viceroy of India, when Quit India Resolution was passed in 1942?
A
Lord Linlithgow
B
Lord Wavell
C
Lord Willingdon
D
Lord Mountbatten
Question 18
When was the East India Association set up?
A
1866
B
1857
C
1836
D
1885
Question 19
Who was the Spanish navigator who set out to discover India, but instead landed on the soil of America?
A
Christopher Columbus
B
Vasco Da Gama
C
James Cook
D
None of above
Question 20
Which dynasty was ruling over north India when Alexander the great invaded India?
A
Gupta Dynasty
B
Maurya Dynasty
C
Sakya Dynasty
D
Nanda Dynasty
Question 21
The roads of cities in the Indus Valley Civilization generally divided the city into
A
Rectangular Blocks
B
Circular Blocks
C
Triangular Blocks
D
None of above
Question 22
In which year was Pulitzer Prize established?
A
1917
B
1918
C
1922
D
1928
Question 23
‘Kanchipuram’ is in which of the following states?
A
Andhra Pradesh
B
Orissa
C
Kerala
D
Tamil Nadu
Question 24
Which of the following is not a chief organ of the United Nations Organizations?
A
International Labour Organisation
B
Security Council
C
International Court of Justice
D
General Assembly
Question 25
Which of the following is not a member of G-15?
A
Indonesia
B
Malaysia
C
Columbia
D
India
Question 26
The group of metals Co, Ni, Fe may best called as
A
Transition metals
B
Main group metals
C
Alkali metals
D
Rare metals
Question 27
Non stick cooking utensils are coated with
A
Black paint
B
PVC
C
Teflon
D
Polystyrene
Question 28
The international township built near Pondicherry in India in coloration with UNEESCO is called
A
Elbaville
B
Auroville
C
Gayaville
D
Broadway
Question 29
Irvin sold a book at a profit of 12%. If Irvin had sold it for Rs. 18 more, then 18% would have been gained. Find the cost price.
A
Rs. 600
B
Rs. 300
C
Rs. 400
D
Rs. 200
Question 29 Explanation: 
Explanation: Let CP = 100%
Sold on 12% profit means sold on 112%
now 18% would have been gained means 118% if Rs 18 was more it means 118% - 112% = 18 Rs
so 6%=18Rs
so 100% = (18/6)×100 = 3× 100 = 300 Rs
CP = 300
Question 30
In a group of 7 people, the average age is found to be 17 years. Two more people joined with an average age 19 years. One person left the group whose age was 25 years. What is the new average age of the group?
A
17.5 Years
B
16.5 Years
C
18 Years
D
16 Years
Question 30 Explanation: 
7 people, the average age is found to be 17 years means 17 * 7 = 119
Two more joined with an average age 19 years means 19 * 2 = 38 So total is 157
But one person left from that group whose age is 25 years 157 - 25 = 132
Remaining average of 8 people is 132 / 8
16.5 Year
Question 31
A 300 meter long metro train crosses a platform in a metro station in 39 seconds while it crosses a lamp post in 18 seconds. What is the length of the platform?
A
250 meter
B
350 meter
C
520 meter
D
300 meter
Question 31 Explanation: 
Speed = Distance/time = 300/18 = 50/3 m/sec
Let the length of the platform be x meters
Distance = Speed * Time
x+300 = (50/3) * 39
x = 350
Question 32
Assume that a sum of money is divided equally among n girls. Each girl will receive $ 60. If another girl is added to the group and the sum is divided equally among all the girls, each child girl a $ 50 share. What is the sum of money?
A
$ 3000
B
$ 300
C
$ 110
D
$ 10
Question 32 Explanation: 
From that question 60 * n = 50 (n + 1)
n = 5
so sum of money is 60 * 5 = 300
Question 33
A tank can be filled by one tap in 10 minutes and by another in 30 minutes. Both the taps are kept open for 5 minutes and then the first one is shut off. In how many minutes more is the tank completely filled?
A
5
B
7.5
C
10
D
12
Question 33 Explanation: 
A tank can be filled in 10 mins
another one is in 30 mins and those taps are opened for 5 mins
so in one min one tap is 1/10 another one is 1/30
both can tank open for 5 mins so (1/10 + 1/30 ) * 5
= (2/15) * 5
= 10/15
= 2⁄3
Remaining work is 1- (2⁄3)
= 1⁄3
The left work has to be done by first Tap because first is shut off.
Work will be completed by Second Tap in= (1⁄3) * 30 = 10
Question 34
From the four choices provided, choose the analogy that is most similar to the one in the question.
Wealth : Poverty
A
part: whole
B
good: excellent
C
prodigal : chary
D
wicked : sinful
Question 34 Explanation: 
Wealth is opposite to Poverty and Prodigal opposite word is chary.
Wealth: an abundance of valuable possessions or money
Poverty: The state of being extremely poor.
Prodigal: spending money or using resources freely and recklessly
chary: Cautiously or suspiciously reluctant to do something.
Question 35
From the four choices provided, choose the analogy that is most similar to the one in the question.
Misfortune : Catastrophe
A
miniature : big
B
limited : infinite
C
knowledge : learning
D
generosity : parsimony
Question 35 Explanation: 
Misfortune is related to Catastrophe and knowledge is related to learning.
Misfortune: An unfortunate condition or event.
Catastrophe: An event causing great and usually sudden damage or suffering.
Question 36
From the four choices provided, choose the analogy that is most similar to the one in the question.
Molecule : Atoms
A
family : sisters
B
light : bulb
C
tissue : cells
D
body : limb
Question 36 Explanation: 
Molecule is a group of atoms bonded together.
Tissue is any of the distinct types of material of which animals or plants are made, consisting of specialized cells and their products.
Question 37
From the four choices provided, choose the analogy that is most similar to the one in the question.
Limp : Walk
A
flap : fly
B
run : race
C
stutter : talk
D
chew : digest
Question 37 Explanation: 
Limp is related to walk and shutter is related to talk.
Limp: Walk with difficulty, typically because of a damaged or stiff leg or foot.
Question 38
From the four choices provided, choose the analogy that is most similar to the one in the question.
Riddle : Solve
A
mirage : illusion
B
joke : amuse
C
tangle : unravel
D
target : aim
Question 38 Explanation: 
Riddle is related to Solve and tangle is related to unravel
Riddle: A question or statement intentionally phrased so as to require ingenuity in ascertaining its answer or meaning.
Tangle: Twist together into a confused mass.
unravel: undo (twisted, knitted, or woven threads).
Question 39
Fact 1 : All chickens are birds.
Fact 2 : Some chickens are hens.
Fact 3 : Female birds lay eggs.
If the first three statements are facts, which of the following statements must also be a fact? i. All birds lay eggs.
ii. Hens are birds.
iii. Some chickens are not hens.
A
ii only
B
ii and iii only
C
I, ii and iii
D
None of the statements is a known fact
Question 39 Explanation: 

According to venn diagram, (i) is FALSE because male birds never lay eggs. (ii) and (iii) are TRUE
Question 40
What is the most essential thing for election?
A
President
B
Voter
C
November
D
Nation
Question 41
What is the most essential thing for ovation?
A
Outburst
B
bravo
C
applause
D
encore
Question 42
Introducing a man to her husband, a woman said, “His brother’s father is the only son of my grandfather.”How is the woman related to this man?
A
Mother
B
Aunt
C
Sister
D
Daughter
Question 42 Explanation: 
Only son of her grandfather -- Her father;
Man's brother's father -- man's father.
So, man's father is her father i.e., She is the man's sister.
Question 43
Pointing to a photograph, a man said, “I have no brother or sister but that man’s father is my father’s son.” Whose photograph was it?
A
His Own
B
His Son
C
His Father
D
His Grandfather
Question 43 Explanation: 
Since the person who is telling has no brother or sister, so his father son is he himself.
So the man in the photograph is his son.
Question 44
Find the number of quadrilaterals in the given figure.
A
6
B
7
C
9
D
11
Question 44 Explanation: 
→ The word "quadrilateral" is derived from the Latin words quadri, a variant of four, and latus, meaning "side".
→ A quadrilateral is a polygon with four edges (or sides) and four vertices or corners.
→ According to figure, we can label first and get total quadrilaterals.

Quadrilaterals are 1234, 1245, 1246, 1248, 3481, 3451, 3461, 4517, 4561, 6178 and 1748.
Question 45
Count the number of convex pentagons in the adjoining figure.
A
16
B
12
C
8
D
4
Question 45 Explanation: 
A convex polygon is a simple polygon (not self-intersecting) in which no line segment between two points on the boundary ever goes outside the polygon.

The pentagons are 12468, 34682, 56824, 78246, 13467, 35681, 57823, 71245, 24578, 46712, 68134 and 82356.
Question 46
There is a family of six people whose nicknames are Pat, Qat, Rat, Sat, Tat and Uat. Their professionals are Engineer, Doctor, Teacher, Salesman, Manager and Lawyer. There are two married couples in the family. The Manager is the grandfather of Uat, who is an Engineer Rat, the Salesman, is married to the lady Teacher Qat is the mother of Uat and Tat. The Doctor, Sat is married to the Manager.

How many male members are there in the family?
A
Two
B
Three
C
Four
D
Data Inadequate
Question 46 Explanation: 
Question 47
There is a family of six people whose nicknames are Pat, Qat, Rat, Sat, Tat and Uat. Their professionals are Engineer, Doctor, Teacher, Salesman, Manager and Lawyer. There are two married couples in the family. The Manager is the grandfather of Uat, who is an Engineer Rat, the Salesman, is married to the lady Teacher Qat is the mother of Uat and Tat. The Doctor, Sat is married to the Manager.

What is the professional of Pat?
A
Lawyer
B
Lawyer or Teacher
C
Manager
D
None of these
Question 47 Explanation: 
Question 48
There is a family of six people whose nicknames are Pat, Qat, Rat, Sat, Tat and Uat. Their professionals are Engineer, Doctor, Teacher, Salesman, Manager and Lawyer. There are two married couples in the family. The Manager is the grandfather of Uat, who is an Engineer Rat, the Salesman, is married to the lady Teacher Qat is the mother of Uat and Tat. The Doctor, Sat is married to the Manager.

Who are the married couples in the family?
A
Pat-Qat and Sat-Rat
B
Rat-Uat and Sat-Tat
C
Pat-Tat and Sat-Rat
D
Pat-Sat and Rat-Qat
Question 48 Explanation: 
Question 49
There is a family of six people whose nicknames are Pat, Qat, Rat, Sat, Tat and Uat. Their professionals are Engineer, Doctor, Teacher, Salesman, Manager and Lawyer. There are two married couples in the family. The Manager is the grandfather of Uat, who is an Engineer Rat, the Salesman, is married to the lady Teacher Qat is the mother of Uat and Tat. The Doctor, Sat is married to the Manager.

How Pat is related to Tat?
A
Father
B
Grandfather
C
Mother
D
Grandmother
Question 49 Explanation: 
Question 50
Shirin went to a bakery and bought items worth Rs. 25, out of which 30 paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items?
A
Rs. 12
B
Rs. 19.70
C
Rs. 19.10
D
Rs. 18.80
Question 50 Explanation: 
Total cost of the items he purchased = Rs.25
Given that out of this Rs.25, 30 Paise is given as tax => Total tax incurred = 30 Paise = Rs.30/100
Let the cost of the tax free items = x
Given that tax rate = 6%
( 25 - 30/100 - x ) * (6/100) = 30 / 100
6(25−0.3−x)=30
x=25−0.3−5=19.7
Question 51
The rate of simple interest on a sum of money is 6 percent per annum for the first 3 years, 8 per cent per annum for the next 5 years and 10 per cent per annum for the period beyond 8 years. If the simple interest accrued by the sum for a total period of 10 years is Rs. 1,560, what is the sum?
A
Rs. 1,500
B
Rs. 3,000
C
Rs. 2,000
D
Data Inadequate
Question 51 Explanation: 
Sum = (1560 * 100 ) / ( 3 * 6 + 8 * 5 + 2 * 10 ) = 2000
Question 52
Adrian starts a start-up with a capital of Rs. 85,000. Brian joins in the start-up with Rs. 42,500 after sometime. For how much period does Brian join, if the profits at the end of the year are divided in the ratio of 3 : 1?
A
5 months
B
6 months
C
7 months
D
8 months
Question 52 Explanation: 
Let B joins for X months.
Then,
(Profit of A)/(Profit of B) = 3/1
(85000 * 12)/(42500 *X) = 3/1
85000 * 12 = 42500 * 3 * X
X = 8.
B Joined for 8 months
Question 53
A car travels at an average of 50 miles per hour for 2.5 hours and then travels at a speed of 70 miles per hour for 1.5 hours. How far did the car travel in the entire 4 hours?
A
210 miles
B
230 miles
C
250 miles
D
260 miles
Question 53 Explanation: 
Speed= 50 miles/ hour Time=2.5 hour
speed=70 miles / hour Time=1.5 hour
Speed= Distance/ time
Distance= speed x Time
=50×2.5+70×1.5
=125+105
=230 miles
Question 54
By selling 45 limes for Rs. 40, a woman loses 20%. How many should she sell for Rs. 24 to gain 20% in the transaction?
A
16
B
18
C
20
D
22
Question 54 Explanation: 
SP of 45 limes is Rs.40
loss = 20%
So CP of 45 limes would be 40*100/80= Rs. 50
To gain 20% She should sell these 45 limes for =50*20/100=Rs. 60
Now If she sells for Rs. 60 = 45 limes
So for Rs. 24 he would sell = (24/60)*45 = 18 limes
Question 55
The prestigious Ramon Magsaysay Award was conferred upon Ms. Kiran Bedi for her excellent contribution to which of the following fields?
A
Literature
B
Community Welfare
C
Government
D
Journalism
Question 56
Who among the following is not a recipient of ‘Dada Saheb Phalke’ Award?
A
Ramanand Sagar
B
Raj Kapoor
C
V. Shantaram
D
Ashok Kumar
Question 57
What is part of a database that holds only one type of information?
A
Report
B
Field
C
Record
D
File
Question 57 Explanation: 
Record holds only specific and one type of information.
Question 58
‘.JPG’ extension refers usually to what kind of file?
A
System file
B
Animation/movie file
C
MS Encarta document
D
Image file
Question 58 Explanation: 
‘.JPG’ extension used for image files.
Question 59
Which of the following is not written by Munshi Premchand?
A
Gaban
B
Godan
C
Guide
D
Manasorovar
Question 60
The famous Dilwara Temples are situated in
A
Uttar Pradesh
B
Rajasthan
C
Maharashtra
D
Madhya Pradesh
There are 60 questions to complete.

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